Answer: D
\[ \frac{2\tan 30^\circ}{1 - \tan^2 30^\circ} = \frac{2 \times \frac{1}{\sqrt{3}}}{1 - \left(\frac{1}{\sqrt{3}}\right)^2} = \frac{\frac{2}{\sqrt{3}}}{\frac{3 - 1}{3}} = \frac{2}{\sqrt{3}} \times \frac{3}{2} = \sqrt{3} \]
\[ \frac{2\tan 30^\circ}{1 - \tan^2 30^\circ} = \frac{2 \times \frac{1}{\sqrt{3}}}{1 - \left(\frac{1}{\sqrt{3}}\right)^2} = \frac{\frac{2}{\sqrt{3}}}{\frac{3 - 1}{3}} = \frac{2}{\sqrt{3}} \times \frac{3}{2} = \sqrt{3} \]