From a solid hemisphere with radius \(r\) units, the volume of the largest solid cone that can be carved out is \(\frac{\pi r^3}{3}\) cubic units.
In this case, the height of the cone \((h)\) is equal to the radius of the hemisphere, i.e., \(h = r\) units. Therefore, the volume of the cone is: \[ = \frac{1}{3} \pi r^2 h = \frac{1}{3} \pi r^2 \cdot r \quad [\text{because } h = r] = \frac{\pi r^3}{3} \text{ cubic units} \]