Q.If \(\frac{a}{2} = \frac{b}{3} = \frac{c}{4} = \frac{3a - 2b + 4c}{p}\), then what is the value of \(p\)? (a) 12 (b) 13 (c) 16 (d) 18
Answer: C
\[ \frac{a}{2} = \frac{b}{3} = \frac{c}{4} \] \[ = \frac{3a}{6} = \frac{-2b}{-6} = \frac{4c}{16} \] \[ = \frac{3a - 2b + 4c}{6 - 6 + 16} = \frac{3a - 2b + 4c}{16} \] \[ \therefore \frac{3a - 2b + 4c}{16} = \frac{3a - 2b + 4c}{p} \Rightarrow p = 16 \]
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