\[ \sin (\theta + 30^\circ) = \cos 15^\circ \Rightarrow \sin (\theta + 30^\circ) = \sin(90^\circ - 15^\circ) \Rightarrow \theta + 30^\circ = 90^\circ - 15^\circ \Rightarrow \theta = 75^\circ - 30^\circ \Rightarrow \theta = 45^\circ \Rightarrow 2\theta = 90^\circ \therefore \cos 2\theta = \cos 90^\circ = 0 \quad \text{[Answer]} \]