When the right-angled triangle is rotated once completely around its longer side adjacent to the right angle, the solid formed is a right circular cone with base radius \(r = 3\) cm and height \(h = 4\) cm. \(\therefore\) Slant height \(l = \sqrt{4^2 + 3^2} = \sqrt{25} = 5\) cm \(\therefore\) Total surface area of the cone = \(\pi r(r + l)\) \(= \frac{22}{7} \times 3 \times (3 + 5)\) square cm \(= \frac{22 \times 3 \times 8}{7} = 75.429\) square cm And volume of the cone = \(\frac{1}{3} \pi r^2 h\) \(= \frac{1}{3} \times \frac{22}{7} \times 3^2 \times 4\) cubic cm \(= \frac{22 \times 9 \times 4}{3 \times 7} = 37.714\) cubic cm