Answer: B
Here’s the English translation of your full solution: --- \[ \tan \theta + \cot \theta = (\sqrt{\tan \theta})^2 + (\sqrt{\cot \theta})^2 = (\sqrt{\tan \theta} - \sqrt{\cot \theta})^2 + 2\sqrt{\tan \theta} \cdot \sqrt{\cot \theta} \] \[ = (\sqrt{\tan \theta} - \sqrt{\cot \theta})^2 + 2\sqrt{\tan \theta \cdot \cot \theta} = (\sqrt{\tan \theta} - \sqrt{\cot \theta})^2 + 2 \quad [\because \tan \theta \cdot \cot \theta = 1] \] Since the square of any real number cannot be negative, \[ \tan \theta + \cot \theta \ge 2 \] ∴ The minimum value of \( \tan \theta + \cot \theta \) is 2
Here’s the English translation of your full solution: --- \[ \tan \theta + \cot \theta = (\sqrt{\tan \theta})^2 + (\sqrt{\cot \theta})^2 = (\sqrt{\tan \theta} - \sqrt{\cot \theta})^2 + 2\sqrt{\tan \theta} \cdot \sqrt{\cot \theta} \] \[ = (\sqrt{\tan \theta} - \sqrt{\cot \theta})^2 + 2\sqrt{\tan \theta \cdot \cot \theta} = (\sqrt{\tan \theta} - \sqrt{\cot \theta})^2 + 2 \quad [\because \tan \theta \cdot \cot \theta = 1] \] Since the square of any real number cannot be negative, \[ \tan \theta + \cot \theta \ge 2 \] ∴ The minimum value of \( \tan \theta + \cot \theta \) is 2