Q.A hollow metallic sphere has an inner radius of 3 cm and an outer radius of 5 cm. It is melted to form a solid right circular cylinder of height \(\frac{8}{3}\) cm. Find the diameter of the base of the cylinder.

Volume of the hollow sphere = \(\cfrac{4}{3}\pi (5^3 - 3^3)\) cubic cm = \(\cfrac{4}{3}\pi (125 - 27)\) cubic cm = \(\cfrac{4 \times 98}{3}\pi\) cubic cm Let the radius of the right circular cylinder be \(r\) cm According to the question: \(\pi r^2 \times \cfrac{8}{3} = \cfrac{4 \times 98}{3}\pi\) ⇒ \(r^2 = \cfrac{4 \times 98}{8} = 49\) ⇒ \(r = 7\) ∴ Diameter of the cylinder = \(2 \times 7 = 14\) cm
Similar Questions