Volume of the hollow sphere = \(\cfrac{4}{3}\pi (5^3 - 3^3)\) cubic cm = \(\cfrac{4}{3}\pi (125 - 27)\) cubic cm = \(\cfrac{4 \times 98}{3}\pi\) cubic cm Let the radius of the right circular cylinder be \(r\) cm According to the question: \(\pi r^2 \times \cfrac{8}{3} = \cfrac{4 \times 98}{3}\pi\) ⇒ \(r^2 = \cfrac{4 \times 98}{8} = 49\) ⇒ \(r = 7\) ∴ Diameter of the cylinder = \(2 \times 7 = 14\) cm