Answer: B
Let’s assume the time \((t)=x\) years
\(\therefore\) Rate of interest \((r)=x\%\)
Principal \((p)=144 \) rupees
\(\therefore\) Total interest \((I)=25\) rupees
or, \(\cfrac{ptr}{100}=25\)
or, \(\cfrac{144\times x\times x}{100}=25\)
or, \(x^2=\cfrac{25\times \cancel{100}25}{\cancel{144}36}\)
or, \(x=\cfrac{25}{6}=4\cfrac{1}{6}\)
\(\therefore\) Time will be \(4\cfrac{1}{6}\) years
Let’s assume the time \((t)=x\) years
\(\therefore\) Rate of interest \((r)=x\%\)
Principal \((p)=144 \) rupees
\(\therefore\) Total interest \((I)=25\) rupees
or, \(\cfrac{ptr}{100}=25\)
or, \(\cfrac{144\times x\times x}{100}=25\)
or, \(x^2=\cfrac{25\times \cancel{100}25}{\cancel{144}36}\)
or, \(x=\cfrac{25}{6}=4\cfrac{1}{6}\)
\(\therefore\) Time will be \(4\cfrac{1}{6}\) years