Answer: B
Let’s assume the principal amount \((p)=8000\) rupees
Time \((t)= 5\) years
Total interest \((I)=(12000-8000)\) rupees = \(4000\) rupees
\(\therefore\) Rate of interest \((r)=\cfrac{100\times I}{pt}\%\)
= \(\cfrac{100\times 4000}{8000\times 5}\%\)
= \(10\%\)
\(\therefore\) Rate of interest is \(10\%\).
Let’s assume the principal amount \((p)=8000\) rupees
Time \((t)= 5\) years
Total interest \((I)=(12000-8000)\) rupees = \(4000\) rupees
\(\therefore\) Rate of interest \((r)=\cfrac{100\times I}{pt}\%\)
= \(\cfrac{100\times 4000}{8000\times 5}\%\)
= \(10\%\)
\(\therefore\) Rate of interest is \(10\%\).