Q.If \(x = \cfrac{4\sqrt{15}}{\sqrt{5} + \sqrt{3}}\), then find the value of \[ \cfrac{x + \sqrt{20}}{x - \sqrt{20}} + \cfrac{x + \sqrt{12}}{x - \sqrt{12}}. \]

Let \[ x = \cfrac{4\sqrt{15}}{\sqrt{5} + \sqrt{3}} = \cfrac{4\sqrt{15}(\sqrt{5} - \sqrt{3})}{(\sqrt{5} + \sqrt{3})(\sqrt{5} - \sqrt{3})} = \cfrac{4\sqrt{15}(\sqrt{5} - \sqrt{3})}{5 - 3} = 2\sqrt{15}(\sqrt{5} - \sqrt{3}) = 10\sqrt{3} - 6\sqrt{5} \] Now, \[ \cfrac{x + \sqrt{20}}{x - \sqrt{20}} = \cfrac{10\sqrt{3} - 6\sqrt{5} + 2\sqrt{5}}{10\sqrt{3} - 6\sqrt{5} - 2\sqrt{5}} = \cfrac{10\sqrt{3} - 4\sqrt{5}}{10\sqrt{3} - 8\sqrt{5}} = \cfrac{5\sqrt{3} - 2\sqrt{5}}{5\sqrt{3} - 4\sqrt{5}} = \cfrac{(5\sqrt{3} - 2\sqrt{5})(5\sqrt{3} + 4\sqrt{5})}{(5\sqrt{3} - 4\sqrt{5})(5\sqrt{3} + 4\sqrt{5})} = \cfrac{35 + 10\sqrt{15}}{-5} = -7 - 2\sqrt{15} \] Similarly, \[ \cfrac{x + \sqrt{12}}{x - \sqrt{12}} = \cfrac{10\sqrt{3} - 6\sqrt{5} + 2\sqrt{3}}{10\sqrt{3} - 6\sqrt{5} - 2\sqrt{3}} = \cfrac{12\sqrt{3} - 6\sqrt{5}}{8\sqrt{3} - 6\sqrt{5}} = \cfrac{6\sqrt{3} - 3\sqrt{5}}{4\sqrt{3} - 3\sqrt{5}} = \cfrac{(6\sqrt{3} - 3\sqrt{5})(4\sqrt{3} + 3\sqrt{5})}{(4\sqrt{3} - 3\sqrt{5})(4\sqrt{3} + 4\sqrt{3})} = \cfrac{27 + 6\sqrt{15}}{3} = 9 + 2\sqrt{15} \] Therefore, \[ \cfrac{x + \sqrt{20}}{x - \sqrt{20}} + \cfrac{x + \sqrt{12}}{x - \sqrt{12}} = -7 - 2\sqrt{15} + 9 + 2\sqrt{15} = 2 \][Answer]
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