Let the first odd number be \(x\). Then, the next consecutive odd number is \((x + 2)\). According to the question: \[ x(x + 2) = 783 \Rightarrow x^2 + 2x - 783 = 0 \Rightarrow x^2 + 29x - 27x - 783 = 0 \Rightarrow x(x + 29) - 27(x + 29) = 0 \Rightarrow (x + 29)(x - 27) = 0 \] So either: \[ x + 29 = 0 \Rightarrow x = -29 \quad \text{(Not acceptable as it's negative)} \text{or} \quad x - 27 = 0 \Rightarrow x = 27 \] ∴ The two numbers are 27 and 29.