Principal \((p) = ₹500\), Rate of interest \((r) = 10\%\) per annum Compound amount \( = ₹500 + ₹105 = ₹605\) Let time \( = n \) years \(\therefore 605 = 500\left(1 + \frac{10}{100}\right)^n\) Or, \(605 = 500\left(1 + \frac{1}{10}\right)^n\) Or, \(\left(\frac{11}{10}\right)^n = \frac{605}{500}\) Or, \(\left(\frac{11}{10}\right)^n = \frac{121}{100} = \left(\frac{11}{10}\right)^2\) So, \(n = 2\) \(\therefore\) At an annual compound interest rate of 10%, ₹105 interest will accumulate in 2 years on ₹500.