Answer: B
The circumference of the vertical cylindrical pipe will be 110 cm. Let the radius be \(r\) cm. ∴ \(2\pi r = 110\) i.e., \(2 \times \frac{22}{7} \times r = 110\) i.e., \(r = 110 \times \frac{7}{22 \times 2}\) i.e., \(r = \frac{35}{2}\) ∴ The diameter of the pipe will be \(\frac{35}{2} \times 2\) cm = 35 cm.
The circumference of the vertical cylindrical pipe will be 110 cm. Let the radius be \(r\) cm. ∴ \(2\pi r = 110\) i.e., \(2 \times \frac{22}{7} \times r = 110\) i.e., \(r = 110 \times \frac{7}{22 \times 2}\) i.e., \(r = \frac{35}{2}\) ∴ The diameter of the pipe will be \(\frac{35}{2} \times 2\) cm = 35 cm.