Answer: C
\(\angle\)ACB = 90° (Angle in a semicircle)
\(\angle\)CAB = 180° - (65° + 90°) = 25°
\(\therefore \angle\)DAB = 40° + 25° = 65°
\(\therefore \angle\)BCD = 180° - 65° = 115°
\(\angle\)ACB = 90° (Angle in a semicircle)
\(\angle\)CAB = 180° - (65° + 90°) = 25°
\(\therefore \angle\)DAB = 40° + 25° = 65°
\(\therefore \angle\)BCD = 180° - 65° = 115°