Q.The center of a circle is O, and AB is its diameter. ABCD is a cyclic quadrilateral. If \(\angle\)ABC = 65° and \(\angle\)DAC = 40°, then the measure of \(\angle\)BCD is—? (a) 75° (b) 105° (c) 115° (d) 80°
Answer: C
\(\angle\)ACB = 90° (Angle in a semicircle)
\(\angle\)CAB = 180° - (65° + 90°) = 25°
\(\therefore \angle\)DAB = 40° + 25° = 65°
\(\therefore \angle\)BCD = 180° - 65° = 115°
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