Answer: D
Let the radii of the two cones be \(2r\) units and \(3r\) units respectively, and their heights be \(5h\) units and \(3h\) units respectively. \(\therefore\) The ratio of their volumes is: \(= \pi (2r)^2 \times 5h : \pi (3r)^2 \times 3h\) \(= 20\pi r^2h : 27\pi r^2h\) \(= 20 : 27\)
Let the radii of the two cones be \(2r\) units and \(3r\) units respectively, and their heights be \(5h\) units and \(3h\) units respectively. \(\therefore\) The ratio of their volumes is: \(= \pi (2r)^2 \times 5h : \pi (3r)^2 \times 3h\) \(= 20\pi r^2h : 27\pi r^2h\) \(= 20 : 27\)