Q.In triangle ABC, a straight line parallel to side BC intersects AB and AC at points D and E respectively. If AE = 2AD, then find the ratio DB : EC.

In triangle ABC, DE ∥ BC ∴ \(\frac{AD}{DB} = \frac{AE}{EC}\) Because AE = 2AD, ∴ \(\frac{AD}{AE} = \frac{1}{2}\) ∴ \(\frac{DB}{EC} = \frac{AD}{AE} = \frac{1}{2}\) ∴ DB : EC = 1 : 2 (Answer)
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