Answer: A
- Given: \(a + b : \sqrt{ab} = 1 : 1\) - That is, \(\cfrac{a + b}{\sqrt{ab}} = \cfrac{1}{1}\) - So, \(\cfrac{a}{\sqrt{ab}} + \cfrac{b}{\sqrt{ab}} = 1\) - Therefore, \(\sqrt{\cfrac{a}{b}} + \sqrt{\cfrac{b}{a}} = 1\)
- Given: \(a + b : \sqrt{ab} = 1 : 1\) - That is, \(\cfrac{a + b}{\sqrt{ab}} = \cfrac{1}{1}\) - So, \(\cfrac{a}{\sqrt{ab}} + \cfrac{b}{\sqrt{ab}} = 1\) - Therefore, \(\sqrt{\cfrac{a}{b}} + \sqrt{\cfrac{b}{a}} = 1\)