Q.If \(sinθ−cosθ=0,\) \( (0°<θ<90°)\) and \(secθ+cosecθ=x\), then the value of \(x\) is—? (a) \(1\) (b) \(2\) (c) \(\sqrt2\) (d) \(2\sqrt2\)
Answer: D
\(sinθ−cosθ=0\)
or, \(sinθ = cosθ = sin(90° - θ)\)
or, \(\theta = 90° - \theta\)
or, \(2\theta = 90°\)
or, \(\theta = 45°\)

\(secθ + cosecθ = x\)
\(\therefore x = sec45° + cosec45° = \sqrt2 + \sqrt2\)
\(= 2\sqrt2\)
So, the value of \(x\) is \(2\sqrt2\).
Similar Questions