Q.If a right circular cone has a height of 12 cm and a volume of \(100\pi\) cubic cm, then what is the radius of the cone?
Let the radius of the base of the cone be \(r\) cm
\(\therefore \frac{1}{3} \pi r^2 \times 12 = 100\pi\)
i.e., \(r^2 = \frac{100 \times 3}{12} = 25\)
\(\therefore r = 5\)
\(\therefore\) The radius of the cone is 5 cm