Answer: D
Let \(\cfrac{a}{b} = \cfrac{b}{c} = \cfrac{c}{d} = k\) Then, \(c = dk\) \(b = ck = dk \cdot k = dk^2\) \(a = bk = dk^2 \cdot k = dk^3\) Now, \(\cfrac{a^2 + b^2 + c^2}{b^2 + c^2 + d^2}\) \(= \cfrac{d^2k^6 + d^2k^4 + d^2k^2}{d^2k^4 + d^2k^2 + d^2}\) \(= \cfrac{d^2k^2(k^4 + k^2 + 1)}{d^2(k^4 + k^2 + 1)}\) \(= k^2\) \(= \cfrac{dk^2}{d}\) \(= \cfrac{b}{d}\)
Let \(\cfrac{a}{b} = \cfrac{b}{c} = \cfrac{c}{d} = k\) Then, \(c = dk\) \(b = ck = dk \cdot k = dk^2\) \(a = bk = dk^2 \cdot k = dk^3\) Now, \(\cfrac{a^2 + b^2 + c^2}{b^2 + c^2 + d^2}\) \(= \cfrac{d^2k^6 + d^2k^4 + d^2k^2}{d^2k^4 + d^2k^2 + d^2}\) \(= \cfrac{d^2k^2(k^4 + k^2 + 1)}{d^2(k^4 + k^2 + 1)}\) \(= k^2\) \(= \cfrac{dk^2}{d}\) \(= \cfrac{b}{d}\)