Q.ABCD is a cyclic quadrilateral. Chord DE is the external bisector of \(\angle BDC\). Prove that AE (or the extended AE) is the external bisector of \(\angle BAC\).

In the cyclic quadrilateral ABCD, DE is the external bisector of \(\angle BDC\). We need to prove that AE is the external bisector of \(\angle BAC\). Construction: Extend CD to point F and BA to point G. Proof: In cyclic quadrilateral AEDB, ∵ The exterior angle of a cyclic quadrilateral is equal to the opposite interior angle ∴ \(\angle EAG = \angle EDB\) Since DE is the external bisector of \(\angle BDC\), \(\angle EDB = \angle EDF\) ∴ \(\angle EAG = \angle EDF\) — (i) Now, in cyclic quadrilateral ACDE, ∵ The exterior angle equals the opposite interior angle ∴ \(\angle EDF = \angle EAC\) — (ii) From (i) and (ii), \(\angle EAG = \angle EAC\) ∴ AE is the external bisector of \(\angle BAC\) (Proved)
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