Q.Given: ∠ABC = 90° and BD ⊥ AC; BD = 6 cm and AD = 4 cm. Find the length of CD.

Triangles ABD and BDC are similar. Let CD = \(x\) cm. ∴ \(\cfrac{CD}{BD} = \cfrac{BD}{AD}\) ⇒ \(\cfrac{x}{6} = \cfrac{6}{4}\) ⇒ \(4x = 36\) ⇒ \(x = 9\) ∴ CD = 9 cm.
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