Since \(a โ \frac{1}{c}\) and \(c โ \frac{1}{b}\), โด \(a = \frac{k_1}{c}\) and \(c = \frac{k_2}{b}\) [where \(k_1\) and \(k_2\) are non-zero proportional constants] Now, \[ a = \frac{k_1}{c} = \frac{k_1}{\frac{k_2}{b}} = \frac{k_1}{k_2} \times b \] Therefore, \(a โ b\) [since \(k_1\) and \(k_2\) are constants]