Given: \( \cos^2 θ - \sin^2 θ = \cfrac{1}{2} \) i.e., \( \cos^2 θ - (1 - \cos^2 θ) = \cfrac{1}{2} \) i.e., \( \cos^2 θ - 1 + \cos^2 θ = \cfrac{1}{2} \) i.e., \( 2\cos^2 θ = \cfrac{1}{2} + 1 = \cfrac{3}{2} \) i.e., \( \cos^2 θ = \cfrac{3}{4} \) i.e., \( \sec^2 θ = \cfrac{4}{3} \) i.e., \( 1 + \tan^2 θ = \cfrac{4}{3} \) i.e., \( \tan^2 θ = \cfrac{4}{3} - 1 = \cfrac{1}{3} \) Answer: \( \tan^2 θ = \cfrac{1}{3} \)