Answer: A
In \(\triangle\)ABC, PQ \(\parallel\) BC,
\(\therefore \cfrac{AP}{PB} = \cfrac{AQ}{QC}\)
\(\therefore \cfrac{PB}{QC} = \cfrac{AP}{AQ} = \cfrac{1}{2}\)
In \(\triangle\)ABC, PQ \(\parallel\) BC,
\(\therefore \cfrac{AP}{PB} = \cfrac{AQ}{QC}\)
\(\therefore \cfrac{PB}{QC} = \cfrac{AP}{AQ} = \cfrac{1}{2}\)
\([\because AQ = 2AP, \therefore \cfrac{AP}{AQ} = \cfrac{1}{2}]\)
\(\therefore\) PB:QC = 1:2.