Q.A straight line parallel to side BC of \(\triangle\)ABC intersects AB and AC at points P and Q, respectively. If AQ = 2AP, then what is the ratio PB:QC? (a) 1:2 (b) 2:1 (c) 1:1 (d) None of these
Answer: A
In \(\triangle\)ABC, PQ \(\parallel\) BC,
\(\therefore \cfrac{AP}{PB} = \cfrac{AQ}{QC}\)
\(\therefore \cfrac{PB}{QC} = \cfrac{AP}{AQ} = \cfrac{1}{2}\)

\([\because AQ = 2AP, \therefore \cfrac{AP}{AQ} = \cfrac{1}{2}]\)

\(\therefore\) PB:QC = 1:2.
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