Answer: A
\( \tan A \tan B = 1 \)
or, \( \tan A = \cfrac{1}{\tan B} = \cot B\)
\( = \tan (90° - B) \)
or, \( A = 90° - B \)
or, \( A + B = 90° \)
∴ \(\cfrac{A + B}{2} = 45° \)
Therefore, \( \tan \cfrac{A + B}{2} = \tan 45° = 1 \).
\( \tan A \tan B = 1 \)
or, \( \tan A = \cfrac{1}{\tan B} = \cot B\)
\( = \tan (90° - B) \)
or, \( A = 90° - B \)
or, \( A + B = 90° \)
∴ \(\cfrac{A + B}{2} = 45° \)
Therefore, \( \tan \cfrac{A + B}{2} = \tan 45° = 1 \).