Answer: A
Let’s assume the principal amount \((p)=10x \) rupees
Interest amount \((I)= (11x-10x)\) rupees
\(\therefore\) Rate of interest \((r) =\cfrac{100\times I}{pt} \%\)
Let’s assume the principal amount \((p)=10x \) rupees
Interest amount \((I)= (11x-10x)\) rupees
\(=x \) rupees
Time \((t)= 1\) year\(\therefore\) Rate of interest \((r) =\cfrac{100\times I}{pt} \%\)
\(=\cfrac{100\times x}{10x\times 1}\%\)
\(=10\%\)