Outer radius of the cylinder \((R) = \frac{10}{2}\) cm = 5 cm ∴ Inner radius \((r) = 5 - 1\) cm = 4 cm And height \((h) = 42\) cm ∴ Amount of iron used in the cylinder \(= \pi(R^2 - r^2) \times h\) cubic cm \(= \frac{22}{7}(5^2 - 4^2) \times 42\) cubic cm \(= \frac{22 \times 9 \times 42}{7}\) cubic cm \(= 1188\) cubic cm ∴ The amount of iron used in the cylinder is 1188 cubic centimeters.