Q.ABCD is a cyclic trapezium, where AD \(\parallel\) BC. If \(\angle\)ABC = 70°, then the measure of \(\angle\)BCD will be—?
(a) 110° (b) 80° (c) 70° (d) 120°
Answer: C
A cyclic trapezium is an isosceles trapezium.
∴ \(\angle\)BCD = \(\angle\)ABC = 70°.
