Given: \(a + b : \sqrt{ab} = 4 : 1\) i.e., \(\frac{a + b}{\sqrt{ab}} = \frac{4}{1}\) i.e., \(\frac{a + b}{2\sqrt{ab}} = \frac{4}{2} = 2\) Now, using the identity for rationalizing: \(\frac{a + b + 2\sqrt{ab}}{a + b - 2\sqrt{ab}} = \frac{2 + 1}{2 - 1} = \frac{3}{1}\) [Using the method of addition and subtraction] i.e., \(\frac{(\sqrt{a} + \sqrt{b})^2}{(\sqrt{a} - \sqrt{b})^2} = \frac{3}{1}\) i.e., \(\frac{\sqrt{a}}{\sqrt{b}} = \frac{\sqrt{3} + 1}{\sqrt{3} - 1}\) Squaring both sides: \(\frac{a}{b} = \left(\frac{\sqrt{3} + 1}{\sqrt{3} - 1}\right)^2\) \(\therefore a : b = (\sqrt{3} + 1)^2 : (\sqrt{3} - 1)^2\)