Q.If \(a : b = b : c\), then prove that \[ (a + b)^2 : (b + c)^2 = a : c \]

Let \(\frac{a}{b} = \frac{b}{c} = k\) \(\therefore a = bk = ck^2\) and \(b = ck\) Now, Left-hand side = \((a + b)^2 : (b + c)^2\) \[ = (ck^2 + ck)^2 : (ck + c)^2 = \{ck(k + 1)\}^2 : \{c(k + 1)\}^2 = c^2k^2(k + 1)^2 : c^2(k + 1)^2 = k^2 : 1 \] Right-hand side = \(a : c\) \[ = ck^2 : c = k^2 : 1 \] \(\therefore\) Left-hand side = Right-hand side (Proved)
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