Let the height of the cone be \(h\) units and the radius be \(r\) units. ∴ Volume of the cone = \(\cfrac{1}{3}\pi r^2 h\) cubic units And volume of the sphere = \(\cfrac{4}{3}\pi r^3\) cubic units According to the question, \(\cfrac{4}{3}\pi r^3 = 2 \times \cfrac{1}{3}\pi r^2 h\) ⇒ \(2r = h\) ⇒ \(\cfrac{r}{h} = \cfrac{1}{2}\) ⇒ \(\cfrac{h}{r} = \cfrac{2}{1}\) ∴ The ratio of the height of the cone to the radius of its base is 2:1.