Q.The radius of the base of a solid right circular cone is equal to the radius of a solid sphere. If the volume of the sphere is twice the volume of the cone, find the ratio of the height of the cone to the radius of its base.

Let the height of the cone be \(h\) units and the radius be \(r\) units. ∴ Volume of the cone = \(\cfrac{1}{3}\pi r^2 h\) cubic units And volume of the sphere = \(\cfrac{4}{3}\pi r^3\) cubic units According to the question, \(\cfrac{4}{3}\pi r^3 = 2 \times \cfrac{1}{3}\pi r^2 h\) ⇒ \(2r = h\) ⇒ \(\cfrac{r}{h} = \cfrac{1}{2}\) ⇒ \(\cfrac{h}{r} = \cfrac{2}{1}\) ∴ The ratio of the height of the cone to the radius of its base is 2:1.
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