Q.If the median of the following data is 32, find the values of \(x\) and \(y\) given that the total frequency is 100.
Class Interval0-1010-2020-3030-4040-5050-60
Frequency10x2530y10

The cumulative frequency distribution table:
Class IntervalFrequencyCumulative Frequency (Less than type)
0-101010
10-20\(x\)10+\(x\)
20-302535+\(x\)
30-403065+\(x\)
40-50\(y\)65+\(x+y\)
50-601075+\(x+y=n\)
Given \(n=100\), Using the condition, \(75+x+y=100\)
Or, \(x+y=25----(i)\)

Since the median is given as 32, The median class is (30-40). โˆด Median formula, \[ M = l + \left[\cfrac{\cfrac{n}{2} - cf}{f}\right] \times h \] where, \(l = 30, n = 100\), \(cf = 35+x, f = 30, h = 10\), \[ M = 30 + \left[\cfrac{50 - (35+x)}{30} \right] \times 10 \] \[ = 30 + \cfrac{15-x}{30} \times 10 \] \[ = 30 + \cfrac{15-x}{3} \] Since \(M = 32\), \[ 30 + \cfrac{15-x}{3} = 32 \] \[ \cfrac{15-x}{3} = 2 \] \[ 15-x = 6 \] \[ x = 9 \] Substituting \(x = 9\) into equation (i), \[ 9 + y = 25 \] \[ y = 16 \] โˆด Required values, \(x = 9, y = 16\).
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