Q.If the product of the roots of the equation \(x^2 - 3x + k = 10\) is \(-2\), then find the value of \(k\).

\(x^2 - 3x + k = 10\) Or, \(x^2 - 3x + k - 10 = 0\) ∴ Product of the roots \(\alpha \beta = \frac{k - 10}{1}\) According to the question, \(k - 10 = -2\) Or, \(k = 10 - 2 = 8\)
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