Answer: B
Let the heights be \(h_1\) and \(h_2\), and the base radii be \(r\) and \(2r\) respectively. \[ \therefore\ \frac{1}{3} \pi r^2 h_1 : \frac{1}{3} \pi (2r)^2 h_2 = 2 : 3 \] i.e., \[ r^2 h_1 : 4r^2 h_2 = 2 : 3 \] i.e., \[ \frac{h_1}{4h_2} = \frac{2}{3} \] i.e., \[ \frac{h_1}{h_2} = \frac{8}{3} \] \(h_1 : h_2 = 8 : 3\).
Let the heights be \(h_1\) and \(h_2\), and the base radii be \(r\) and \(2r\) respectively. \[ \therefore\ \frac{1}{3} \pi r^2 h_1 : \frac{1}{3} \pi (2r)^2 h_2 = 2 : 3 \] i.e., \[ r^2 h_1 : 4r^2 h_2 = 2 : 3 \] i.e., \[ \frac{h_1}{4h_2} = \frac{2}{3} \] i.e., \[ \frac{h_1}{h_2} = \frac{8}{3} \] \(h_1 : h_2 = 8 : 3\).