Q.If \(\angle A + \angle B = 90^\circ\), then prove that \(1 + \frac{\tan A}{\tan B} = \csc^2 B\).

1 + (tan A / tan B) = 1 + (tan(90° − B) / tan B) = 1 + (cot B / cot B) = 1 + cot² B = cosec² B (Proved)
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